POWER CALCULATE:

#include <bits/stdc++.h>

    using namespace std;

    #define LL long long int

    

    

    LL pow(LL a, LL b, LL mod) {

        LL x = 1, y = a;

        while(b > 0) {

            printf("b=%d\n",b);

            if(b%2 == 1) {

                 printf("%d %d\n",x,y);

                x=(x*y);

                if(x>mod)

                x%=mod;

            }

            y = (y*y);

            if(y>mod)

            y%=mod;

               b /= 2;

        printf("x=%d\n",x);  

        }

        return x;

    }

    int main()

    {

        LL A,B,MOD=1000000007;

        cin>>A>>B;

        cout<<pow(A,B,MOD)<<endl;

        return 0;

    }

 #include <bits/stdc++.h> 

 using namespace std;

int main()

  {

 int t;

 long long a,x,d,n,m,ans;

 cin >> t;

 while ( t-- ) {

        cin >> n >> m;

         ans = 0;

        a = 1;

        x = min(n,m);

         d = m+1;

         ans += (x*(2*a + (x-1)*d))/2;

         d = n+1;

        ans += (x*(2*a + (x-1)*d))/2;

        cout << ans << endl;

  }

   return 0;

}