Given a two dimensional array of string like. <”luke”, “shaw”>; <”wayne”, “rooney”>; <”rooney”, “ronaldo”>; <”shaw”, “rooney”>; Where the first string is “child”, second string is “Father”. And given “ronaldo” we have to find his no of grandchildren Here “ronaldo” has 2 grandchildren. So our output should be 2.

#include <stdio.h>

#include <string.h>

int main()

{

char a[10][100],b[10][100],str[100];

int num,k;

scanf("%d",&num);

scanf("%s",&str);

for(int i=0;i<num;i++)

{

scanf("%s%s",&a[i],&b[i]);

if(strcmp(str,b[i]) == 0)

k = i;

}

int count = 0;

for(int i=0;i<num;i++)

{

if(strcmp(a[k],b[i]) == 0)

count++;

}

printf("%d",count);

return 0;

}

OR

#include <iostream>

#include<cstdlib>

using namespace std;

int count=0;

string a[4][2]={

   {"luke", "shaw"},

   {"wayne", "rooney"},

   {"rooney", "ronaldo"},

   {"shaw", "rooney"}

 };

void grandchi(string x){

  for(int i=0;i<4;i++){

 if(x==a[i][1]){

  count++;

 }

  } 

}

int main() {

 string s,s1;

  

 for(int i=0;i<4;i++){

  for(int j=0;j<2;j++){

   cout<<a[i][j]<<"\n";

  }

  

 }

 cout<<"enter string"<<"\n";

 cin>>s;

 cout<<s;

 for(int i=0;i<4;i++){

  if(s==a[i][1]){

   s1=a[i][0];

   grandchi(s1);

  }

 }

 cout<<"grand children:"<<count;

 return 0;

}