CHECK WHETHER THE STRING IS ANAGRAM OR NOT

# include <stdio.h> # define NO_OF_CHARS 256   /* function to check whether two strings are anagram of    each other */ bool areAnagram(char *str1, char *str2) {     // Create 2 count arrays and initialize all values as 0     int count1[NO_OF_CHARS] = {0};     int count2[NO_OF_CHARS] = {0};     int i;       // For each character in input strings, increment count in     // the corresponding count array     for (i = 0; str1[i] && str2[i];  i++)     {         count1[str1[i]]++;         count2[str2[i]]++;     }       // If both strings are of different length. Removing this     // condition will make the program fail for strings like     // "aaca" and "aca"     if (str1[i] || str2[i])       return false;       // Compare count arrays     for (i = 0; i < NO_OF_CHARS; i++)         if (count1[i] != count2[i])             return false;       return true; }   /* Driver program to test to print printDups*/ int main() {     char str1[] = "geeksforgeeks";     char str2[] = "forgeeksgeeks";     if ( areAnagram(str1, str2) )       printf("The two strings are anagram of each other");     else       printf("The two strings are not anagram of each other");       return 0; }